Translations:Angles/11/en

static {

   for (int i = 0; i < 65536; ++i)
   {
       SIN_TABLE[i] = (float)Math.sin((double)i * Math.PI * 2.0D / 65536.0D);
   }

} </syntaxhighlight>Note: & 65535 gives the (positive) remainder of a division by 65536 ( $2^{16}$)