# Translations:Angles/11/en

static {

```   for (int i = 0; i < 65536; ++i)
{
SIN_TABLE[i] = (float)Math.sin((double)i * Math.PI * 2.0D / 65536.0D);
}
```

} </syntaxhighlight>Note: `& 65535` gives the (positive) remainder of a division by 65536 ( ${\displaystyle 2^{16}}$)