Translations:Angles/11/zh

static {

   for (int i = 0; i < 65536; ++i)
   {
       SIN_TABLE[i] = (float)Math.sin((double)i * Math.PI * 2.0D / 65536.0D);
   }

} </syntaxhighlight>注意： & 65535给出除以 65536（$2^{16}$）的（正）余数